Câu hỏi của Trần N.Anh

Question

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a, 1/4 x^2 - ( 1/2x-4)*1/2x=-14

Đức Hiếu · Accepted Answer

$\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right)\dfrac{1}{2}x=-14$

$\Rightarrow\dfrac{1}{4}x^2-\left(\dfrac{1}{4}x^2-2x\right)=-14$

$\Rightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Rightarrow x=-7$

Chúc bạn học tốt!!!Câu trả lời: $\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right)\dfrac{1}{2}x=-14$

$\Rightarrow\dfrac{1}{4}x^2-\left(\dfrac{1}{4}x^2-2x\right)=-14$

$\Rightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Rightarrow x=-7$

Chúc bạn học tốt!!!

qwerty · Answer

$\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right)\cdot\dfrac{1}{2}x=-14$

$\Leftrightarrow\dfrac{1}{4}x^2+\left(-\dfrac{1}{2}x+4\right)\cdot\dfrac{1}{2}x=-14$

$\Leftrightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Leftrightarrow2x=-14$

$\Leftrightarrow x=-7$

Vậy $x=-7$Câu trả lời: $\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right)\cdot\dfrac{1}{2}x=-14$

$\Leftrightarrow\dfrac{1}{4}x^2+\left(-\dfrac{1}{2}x+4\right)\cdot\dfrac{1}{2}x=-14$

$\Leftrightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Leftrightarrow2x=-14$

$\Leftrightarrow x=-7$

Vậy $x=-7$

Hoàng Thị Ngọc Anh · Answer

$\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right).\dfrac{1}{2}x=-14$

$\Rightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Rightarrow2x=-14$

$\Rightarrow x=-14:2$

$\Rightarrow x=-7$

Vậy $x=-7.$Câu trả lời: $\dfrac{1}{4}x^2-\left(\dfrac{1}{2}x-4\right).\dfrac{1}{2}x=-14$

$\Rightarrow\dfrac{1}{4}x^2-\dfrac{1}{4}x^2+2x=-14$

$\Rightarrow2x=-14$

$\Rightarrow x=-14:2$

$\Rightarrow x=-7$

Vậy $x=-7.$

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