Question

Tìm x biết : (2x+3)^2-(x-1)^2=0

Answer 1

\(\left(2x+3\right)^2-\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(2x+3+x-1\right)\left(2x+3-x+1\right)=0\)

\(\Leftrightarrow\left(3x+2\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\x+4=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-\dfrac{2}{3}\\x=-4\end{matrix}\right.\)

Answer 2

\(\left(2x+3\right)^2-\left(x-1\right)^2=0\\ \Leftrightarrow\left(2x+3-x+1\right)\left(2x+3+x-1\right)=0\\ \Leftrightarrow\left(x+4\right)\left(3x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+4=0\\3x+2=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-4\\x=\dfrac{-2}{3}\end{matrix}\right.\)

Answer 3

Há há=)