Question

Tim x :

a) (x^2+x)(x^2+x+1)=6

Answer 1

Answer 2

a ) \(\left(x^2+x\right)\left(x^2+x+1\right)=6\)

\(x^2.\left(x^2+x+1\right)+x.\left(x^2+x+1\right)=6\)

\(x^2.x^2+x^2.x+x^2.x+x.x^2+x.x+x.1=_{ }6\)

\(x^4+x^3+x^3+x^3+x^2+x=6\)

\(x^4+3x^3+x^2+x=6\)

Tới đây .........

Answer 3

Đặt x^2+x=a

Theo bài ra ta có:a.(a+1)=6

\(\Rightarrow\)a=2

thay a=x^2+x ta có

x^2+x=2

\(\Rightarrow\)x.(x+1)=2

\(\Rightarrow\)=1