2x(x - 3) - (x - 3) = 0
\(\Rightarrow\) 2x(x - 3 - x) = -3
\(\Rightarrow\) -6x = -3
\(\Rightarrow\) x = 0,5
2x(x-3)-(x-3)=0=>(2x-1)(x-3)=0
=> 2x-1=0 x=1/2
=>
x-3=0 x=3
vậy x =1/2 hoặc x=3
\(2x\left(x-3\right)-\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\2x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\2x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy x=3 hoặc \(x=\dfrac{1}{2}\)
- Ta có:
\(2x\left(x-3\right)-\left(x-3\right)\)
= \(\left(2x-1\right)\left(x-3\right)=0\)
=> \(\left\{{}\begin{matrix}2x-1=0\\x-3=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{1}{2}\\x=3\end{matrix}\right.\)
- Vậy \(x\in\left(\dfrac{1}{2},3\right)\)
