\(\frac{x-1}{15}=\frac{-60}{1-x}\)
\(\Rightarrow\frac{x-1}{15}=\frac{60}{-\left(1-x\right)}\)
\(\Rightarrow\frac{x-1}{15}=\frac{60}{x-1}\)
\(\Rightarrow\left(x-1\right)^2=900\)
\(\Rightarrow\left[\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
Vậy \(x\in\left\{31;-29\right\}\)
\(\frac{x-1}{15}=\frac{-60}{1-x}\)
\(\Rightarrow\frac{x-1}{15}=\frac{-60}{-x+1}\)
\(\Rightarrow\frac{x-1}{15}=\frac{-60}{-\left(x-1\right)}\)
\(\Rightarrow\frac{x-1}{15}=\frac{60}{x-1}\)
\(\Rightarrow\left(x-1\right)^2=15.60\)
\(\Rightarrow\left(x-1\right)^2=900\)
\(\Rightarrow x-1=\pm30\)
\(\Rightarrow\left\{\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
Vậy...