\(\frac{1}{2}.2^n+4.2^n=9.2^5\)
\(2^n.\left(\frac{1}{2}.4\right)=288\)
\(2^n.2=288\)
\(2^n=288:2\)
\(2^n=144\)
Suy ra n ko tìm được
Ta có :
\(\frac{1}{2}\cdot2^n+4\cdot2^n=\frac{9}{2}\cdot2^5\)
\(=>\left(\frac{1}{2}+4\right)\cdot2^n=9\cdot2^5\)
\(=>\left(\frac{1}{2}+\frac{8}{2}\right)\cdot2^n=9\cdot2^5\)
\(=>\frac{9}{2}\cdot2^n=\frac{9}{2}\cdot2^5\)
\(=>2^n=2^5\)
\(=>n=5\)
\(\frac{1}{2}\times2^n+4\times2^n=9\times2^5\)
\(2^n\times\left(\frac{1}{2}+4\right)=9\times2^5\)
\(2^n\times\left(\frac{1+8}{4}\right)=9\times2^5\)
\(2^n\times\frac{9}{2^2}=9\times2^5\)
\(\frac{2^n}{2^2}=2^5\)
\(2^n=2^5\times2^2\)
\(2^n=2^7\)
\(n=7\)
Sorry
Làm lại nha
\(\frac{1}{2}\times2^n+4\times2^n=9\times2^5\)
\(2^n\times\left(\frac{1}{2}+4\right)=9\times2^5\)
\(2^n\times\left(\frac{1+8}{2}\right)=9\times2^5\)
\(2^n\times\frac{9}{2}=9\times2^5\)
\(\frac{2^n}{2}=2^5\)
\(2^n=2^5\times2\)
\(2^n=2^6\)
\(n=6\)
