Question

tìm số nguyên n biết rằng n-4 chia hết cho n-1

Answer 1

Ta có:

\(n-4=n-1-3\)

Để \(\left(n-4\right)⋮\left(n-1\right)\) thì \(3⋮\left(n-1\right)\)

\(\Rightarrow n-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)

\(\Rightarrow n\in\left\{-2;0;2;4\right\}\)