\(\int\dfrac{1}{2x+3}dx=\dfrac{1}{2}ln\left|2x+3\right|+C\)
ta có \(f\left(2\right)=\dfrac{1}{2}ln\left|2\times2+3\right|+C=\dfrac{1}{2}ln7+C=1\Leftrightarrow C=1-\dfrac{1}{2}ln7\)
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