ĐKXĐ : \(x\ge0\)
Có : \(P=x-\sqrt{x}=\left(\sqrt{x}\right)^2-2.\sqrt{x}.\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}\)
\(=\left(\sqrt{x}-\dfrac{1}{2}\right)^2-\dfrac{1}{4}\ge-\dfrac{1}{4}\)
Dấu "=" xảy ra \(\Leftrightarrow\sqrt{x}-\dfrac{1}{2}=0\Leftrightarrow x=\dfrac{1}{4}\) ( Thỏa mãn )
Vậy Min \(P=\dfrac{1}{4}\) khi \(x=\dfrac{1}{4}\)
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