\(E=\left(x^2-7x\right)\left(x^2-7x+12\right)\)
Đặt \(x^2-7x+6=a\)
=> E = (a-6)(a+6)
= \(a^2-36\) \(\ge-36\)
Dấu "=" xảy ra <=> \(a^2=0< =>\left(x^2-7x+6\right)^2=0\)
<=> \(\left(x-1\right)\left(x-6\right)=0\)
<=> \(\left[{}\begin{matrix}x=1\\x=6\end{matrix}\right.\)