Question

[Tìm cặp số nguyên x,y thỏa mãn] \(\frac{10}{x}+\frac{4}{y}=1\)

Cảm ơn <3 <3

Answer 1

Ta co \(\dfrac{10}{x}+\dfrac{4}{y}=1\)

\(=>\dfrac{10y}{xy}+\dfrac{4x}{xy}=\dfrac{xy}{xy}\)

\(=>10y+4x=xy\)

\(=>10y+4x-xy=0\)

\(=>\left(10y-xy\right)+4x=0\)

\(=>y.\left(10-x\right)-4\left(10-x\right)+40=0\)

\(=>\left(10-x\right).\left(y-4\right)=0-40\)

\(=>\left(10-x\right).\left(y-4\right)=-40\)

10-x	-1	-40	1	40	-2	20	2	-20	-5	-8	5	8	-4	10	4	-10
x	11	50	9	-30	12	-10	8	30	15	18	5	2	14	0	6	20
y-4	40	1	-40	-1	20	-2	-20	2	8	5	-8	-5	10	-4	-10	4
y	44	5	-36	3	24	2	-16	6	12	9	-4	-1	14	0	-6	8

Vậy x,y thuộc {(..) ; (..) ; ...} (bạn tự điền nha)

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