\(\dfrac{x^2+2x}{x-1}\). Q = \(\dfrac{x^2-4}{x^2-x}\)
\(\Leftrightarrow\) Q = \(\dfrac{x^2-4}{x^2-x}\): \(\dfrac{x^2+2x}{x-1}\)
\(\Leftrightarrow\) Q = \(\dfrac{\left(x-2\right)\left(x+2\right)}{x\left(x-1\right)}\) . \(\dfrac{x-1}{x\left(x+2\right)}\)
\(\Leftrightarrow\) Q = \(\dfrac{x-2}{x}\)
Vậy Q = \(\dfrac{x-2}{x}\)