\(1\frac{13}{15}.\left(0,5\right)^2.3+\left(\frac{8}{15}.1\frac{19}{60}\right):1\frac{23}{24}\)
\(=\frac{28}{15}.\frac{1}{4}.3+\left(\frac{8}{15}.\frac{79}{60}\right):\frac{47}{24}\)\(\\ \)
\(=\frac{28.1.3}{15.4}+\frac{8.79}{15.60}.\frac{24}{47}\)
\(=\frac{7}{5}+\frac{8.79.24}{15.60.47}\)
\(=\frac{7}{5}+\frac{1264}{3525}\)
\(=\frac{6199}{3525}\)
Vậy : \(1\frac{13}{15}.\left(0,5\right)^2.3+\left(\frac{8}{15}.1\frac{19}{60}\right):1\frac{23}{24}=\frac{6199}{3525}\)