Question

thực hiện cac phep tinh sau:

a. \(\frac{6x^2+8x+7}{x^3-1}+\frac{x}{x^2+x+1}+\frac{6}{1-x}\)

b. \(\frac{1-x}{x^2-2x+1}+\frac{x+1}{x-1.}\)

mong jup dỡ ạ!

Answer 1

a/\(=\frac{6x^2+8x+7}{x^3-1}+\frac{x}{x^2+x+1}-\frac{6}{x-1}\)=\(\frac{6x^2+8x+7+x\left(x-1\right)-6\left(x^2+x+1\right)}{x^3-1}=\frac{x^2+x+1}{x^3-1}=\frac{1}{x-1}\)

b/\(=\frac{1-x+x^2-1}{\left(x-1\right)^2}=\frac{x\left(x-1\right)}{\left(x-1\right)^2}=\frac{x}{x-1}\)