\(\sqrt{9+6-6\sqrt{6}}\)
= \(\sqrt{\left(3-\sqrt{6}\right)^2}\)
=\(3-\sqrt{6}\)
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Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
\(\dfrac{\sqrt{\sqrt{15}-\sqrt{6}}+\sqrt{\sqrt{15}+\sqrt{6}}}{\sqrt{\sqrt{15}+3}}\)
a,\(\sqrt{9-4\sqrt{5}}\)
b,\(\sqrt{15-6\sqrt{6}}+\sqrt{15+6\sqrt{6}}\)
TÍNH
Giúp mình với!mai nộp r!cảm ơn mn trc nhé!!!!
(các bạn làm đầy đủ bước nhá)
32, sqrt{15-6sqrt{6}}+sqrt{33-12sqrt{6}}
33, sqrt{6-2sqrt{5}}+sqrt{6+2sqrt{5}}
34, sqrt{8-2sqrt{15}}-sqrt{23-4sqrt{15}}
35,sqrt{31-8sqrt{15}}+sqrt{24-6sqrt{15}}
36, sqrt{49-5sqrt{96}}-sqrt{49+5sqrt{96}}
37, sqrt{3+2sqrt{2}}+sqrt{5-2sqrt{6}}
Đọc tiếp
Giúp mình với!mai nộp r!cảm ơn mn trc nhé!!!!
(các bạn làm đầy đủ bước nhá)
32, \(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
33, \(\sqrt{6-2\sqrt{5}}+\sqrt{6+2\sqrt{5}}\)
34, \(\sqrt{8-2\sqrt{15}}-\sqrt{23-4\sqrt{15}}\)
35,\(\sqrt{31-8\sqrt{15}}+\sqrt{24-6\sqrt{15}}\)
36, \(\sqrt{49-5\sqrt{96}}-\sqrt{49+5\sqrt{96}}\)
37, \(\sqrt{3+2\sqrt{2}}+\sqrt{5-2\sqrt{6}}\)
1, dfrac{6-sqrt{6}}{sqrt{6}-1}+dfrac{6+sqrt{6}}{sqrt{6}}
2, dfrac{6-6sqrt{3}}{1-sqrt{3}}+dfrac{3sqrt{3}+3}{sqrt{3}+1}
3, dfrac{3+sqrt{3}}{sqrt{3}}+dfrac{sqrt{6}-sqrt{3}}{1-sqrt{2}}
4, dfrac{sqrt{15}-sqrt{12}}{sqrt{5}-2}+dfrac{6+2sqrt{6}}{sqrt{3}+sqrt{2}}
5, left(dfrac{3sqrt{125}}{15}-dfrac{10-4sqrt{5}}{sqrt{5}-2}right)cdotdfrac{1}{sqrt{5}}
Đọc tiếp
1, \(\dfrac{6-\sqrt{6}}{\sqrt{6}-1}+\dfrac{6+\sqrt{6}}{\sqrt{6}}\)
2, \(\dfrac{6-6\sqrt{3}}{1-\sqrt{3}}+\dfrac{3\sqrt{3}+3}{\sqrt{3}+1}\)
3, \(\dfrac{3+\sqrt{3}}{\sqrt{3}}+\dfrac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}\)
4, \(\dfrac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\dfrac{6+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}\)
5, \(\left(\dfrac{3\sqrt{125}}{15}-\dfrac{10-4\sqrt{5}}{\sqrt{5}-2}\right)\cdot\dfrac{1}{\sqrt{5}}\)
\(\sqrt{15+6\sqrt{6}}-\sqrt{33-12\sqrt{6}}\)
Tính thu gọn :
a , sqrt{17-12sqrt{2}}-sqrt{17+12sqrt{2}}
b , sqrt{27+12sqrt{5}}-sqrt{27-12sqrt{5}}
c , sqrt{15-6sqrt{6}}+sqrt{15+sqrt{6sqrt{6}}}
d , sqrt{4+sqrt{15}}+sqrt{4-sqrt{15}}-2sqrt{3-sqrt{5}}
e , sqrt{17-3sqrt{32}}+sqrt{17+3sqrt{32}}
f , sqrt{5+sqrt{3-sqrt{29-12sqrt{5}}}}
Đọc tiếp
Tính thu gọn :
a , \(\sqrt{17-12\sqrt{2}}-\sqrt{17+12\sqrt{2}}\)
b , \(\sqrt{27+12\sqrt{5}}-\sqrt{27-12\sqrt{5}}\)
c , \(\sqrt{15-6\sqrt{6}}+\sqrt{15+\sqrt{6\sqrt{6}}}\)
d , \(\sqrt{4+\sqrt{15}}+\sqrt{4-\sqrt{15}}-2\sqrt{3-\sqrt{5}}\)
e , \(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}\)
f , \(\sqrt{5+\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
rút gọn
\(\dfrac{2\sqrt{15}-2\sqrt{10}+\sqrt{6}-3}{2\sqrt{15}-2\sqrt{10}-\sqrt{3}+\sqrt{6}}\)
\(\frac{15}{\sqrt{6}+1}+\frac{4}{\sqrt{6}-2}+\frac{12}{\sqrt{6}-3}-\sqrt{6}\)
a) \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
b) \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)