\(2022A=\dfrac{2022^{11}+2022}{2022^{11}+1}=1+\dfrac{2021}{2022^{11}+1}\)
\(2022B=\dfrac{2022^{12}+2022}{2022^{12}+1}=1+\dfrac{2021}{2022^{12}+1}\)
2022^11+1<2022^12+1
=>2022A>2022B
=>A>B
Đúng 0
Bình luận (0)
