Ta có
\(\frac{84}{-83}+1=-\frac{1}{83}=-\frac{6}{498}\)
\(-\frac{337}{331}+1=-\frac{6}{331}\)
Vì \(-\frac{6}{498}>-\frac{6}{331}\)
=> \(-\frac{84}{83}>-\frac{337}{331}\)
Ta có
\(\frac{84}{-83}+1=-\frac{1}{83}=-\frac{6}{498}\)
\(-\frac{337}{331}+1=-\frac{6}{331}\)
Vì \(-\frac{6}{498}>-\frac{6}{331}\)
=> \(-\frac{84}{83}>-\frac{337}{331}\)
So sanh P va Q
P=\(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}\)
Q=\(\frac{2010+2011+2012}{2011+2012+2013}\)
1, So sanh:
a) \(\frac{n+1}{n+5}va\frac{n+2}{n+3}\)
b) \(\frac{n}{n+3}va\frac{n-1}{n+4}\)
1. So sanh :
a) \(\frac{2015.2016-1}{2016.2015}\) va \(\frac{2016.2017-1}{2016.2017}\)
b) \(\frac{2015.2016}{2015.2016+1}\) va \(\frac{2016.2017}{2016.2017+1}\)
c) \(\frac{33.10^3}{2^3.5.10^3+7000}\) va \(\frac{3774}{5271}\)
so sanh ( giai thich nua nhe)
a, 67/77 và 73/83
b, 456/461 va 123/128
c, 11/32 và 16/49
d, 2003x 2004-1/2003x2004 va 2004 x 2005 -1/ 2004x2005
So sanh
\(\frac{1}{101}\)\(+\frac{1}{102}\)\(+...+\frac{1}{199}\)\(+\frac{1}{200}\) voi \(\frac{7}{12}\)
So sánh
a) \(\frac{67}{77}\) và \(\frac{73}{83}\)
b) \(\frac{11}{82}\) và \(\frac{16}{49}\)
so sanh
A=\(\frac{2016^{2016}+1}{2016^{2017}+1}\)
B=\(\frac{2016^{2017}-3}{2016^{2018}-3}\)
So sanh
399 va 1121
So sanh cu the nha
So sanh
399 va 1121
So sanh cu the nha