\(A=3\left(2x-1\right)-\left|x-5\right|\)
th1: \(x-5\ge0\Leftrightarrow x\ge5\)
\(\Rightarrow A=3\left(2x-1\right)-\left|x-5\right|=3\left(2x-1\right)-\left(x-5\right)\)
\(=6x-3-x+5=5x+2\)
th2: \(x-5< 0\Leftrightarrow x< 5\)
\(\Rightarrow A=3\left(2x-1\right)-\left|x-5\right|=3\left(2x-1\right)-\left(5-x\right)\)
\(=6x-3-5+x=7x-8\)
vậy \(A=5x+2;A=7x-8\)