Question

Phân tích thành nhân tử

\(x^2+5x-6\)

\(x^3-x+3^2y+xy^2+y^3-y\)

Answer 1

\(x^2+5x-6\)

\(\Leftrightarrow x^2-x+6x-6\)

\(\Leftrightarrow x\left(x-1\right)+6\left(x-1\right)\)

\(\Leftrightarrow\left(x-1\right)\left(x+6\right)\)

Chúc bạn học tốt 

Answer 2

\(x^3-x+3x^2y+xy^2+y^3-y\)

\(=\left(x^3+3x^2y+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)

\(=\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\)

Answer 3

a.

x² + 5x - 6 = x² + x - 6x - 6 = x(x + 1) - 6(x + 1) = (x - 6)(x + 1)

Answer 4

x²+5x-6=x²+3x+2x-6             =(x²+2x)+(3x-6)             =x(x+2)-3(x+2)             =(x+2)(x-3)x³-x+3²y+xy²+y³-y=(x³-x+xy²)+(9y+y³-y)                              =x(x²-1+y²)+y(9+y²+1)                              = hết bik