Question

phan tich da thuc thanh nhan tu 4x^2 - y ^2+8(y-2)

Answer 1

\(4x^2-y^2+8\left(y-2\right)=4x^2-y^2+8y-16=4x^2-\left(y-4\right)^2=\left(2x-y+4\right)\left(2x+y-4\right)\)