Question

Phân tích đa thức sau thành nhân tử :

x²+2xy+6y-9

Answer 1

\(x^2+2xy+6y-9\)

=> \(x^2-9+2xy+6y\)

=> \(x^2-3^2+2xy+6y\)

=> \(\left(x-3\right)\left(x+3\right)+2y\left(x+3\right)\)

=> \(\left(x+3\right)\left(x-3+2y\right)\)

#Yiin - girl ><

Answer 2

\(x^2+2xy+6y-9\)

\(=\left(x^2-9\right)+\left(2xy+6y\right)\)

\(=\left(x-3\right)\left(x+3\right)+2y\left(x+3\right)\)

\(=\left(x+3\right)\left(x-3+2y\right)\)