Bài 6 :
\(n_{Na}=\dfrac{11,5}{23}=0,5\left(mol\right)\)
Pt : \(2Na+H_2SO_4\rightarrow Na_2SO_4+H_2|\)
2 1 1 1
0,5 0,25 0,25 0,25
a) \(n_{H2}=\dfrac{0,5.1}{2}=0,25\left(mol\right)\)
\(V_{H2\left(dktc\right)}=0,25.22,4=5,6\left(l\right)\)
\(n_{H2SO4}=\dfrac{0,5.1}{2}=0,25\left(mol\right)\)
\(m_{H2SO4}=0,25.98=24,5\left(g\right)\)
\(m_{ddH2SO4}=\dfrac{24,5.100}{20}=122,5\left(g\right)\)
b) \(n_{Na2SO4}=\dfrac{0,25.1}{1}=0,25\left(mol\right)\)
⇒ \(m_{Na2SO4}=0,25.142=35,5\left(g\right)\)
\(m_{ddspu}=11,5+122,5-\left(0,25.2\right)=133,5\left(g\right)\)
\(C_{Na2SO4}=\dfrac{35,5.100}{133,5}=26,6\)0/0
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