Bài 2: Giới hạn của hàm số
Các câu hỏi tương tự
\(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{4x+1}-\sqrt[3]{2x+1}}{x}\)
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{4x+5}-3}{\sqrt[3]{5x+3}-2}\)
\(\lim\limits_{x\rightarrow-1}\dfrac{\sqrt[4]{2x+3}+\sqrt[3]{2+3x}}{\sqrt{x+2}-1}\)
\(\lim\limits_{x\rightarrow1^-}\dfrac{\sqrt{x^2-3x+2}}{x^2-5x+4}\)
\(\lim\limits_{x\rightarrow1}\dfrac{x^3-3x^2+2}{x^2-4x+3}\)
\(\lim\limits_{x\rightarrow1^-}\dfrac{x^2+3x+2}{\left|x+1\right|}\)
\(\lim\limits_{x\rightarrow3}\dfrac{\sqrt[3]{x+5}-2}{x^2-4x+3}\)
\(\lim\limits_{x\rightarrow0}\dfrac{\left(1+3x\right)^3-\left(1-4x\right)^4}{x}\)
\(\lim\limits_{x\rightarrow2}\dfrac{2x^2-5x+2}{x^3-3x-2}\)
\(\lim\limits_{x\rightarrow1}\dfrac{x^4-3x+2}{x^3+2x-3}\)
\(\lim\limits_{x\rightarrow-4}\dfrac{x^2+3x-4}{x^2+4x}\)
\(\lim\limits_{x\rightarrow1^+}\dfrac{\sqrt{x^2-x+3}}{2\left|x\right|-1}\)
1) limlimits_{xrightarrow0}dfrac{sqrt{1+4x}.sqrt[3]{1+6x}.sqrt[4]{1+8x}-1}{x}
2)limlimits_{xrightarrow1}dfrac{sqrt[3]{1+7x}-x^3+3x-4}{x-1}
3) limlimits_{xrightarrow-infty}dfrac{x^3-x^2+1}{2x^2+3x-1}
4) limlimits_{xrightarrow+infty}dfrac{sqrt{x}+sqrt[3]{x}+sqrt[4]{x}}{sqrt{4x+1}}
5) limlimits_{xrightarrow-infty}dfrac{x+sqrt{x^2+2}}{sqrt[3]{8x^3+x^2+1}}
6) limlimits_{xrightarrow-infty}dfrac{sqrt{4x^2+3x-7}}{sqrt[3]{27x^3+5x^2+x-4}}
Đọc tiếp
1) \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{1+4x}.\sqrt[3]{1+6x}.\sqrt[4]{1+8x}-1}{x}\)
2)\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[3]{1+7x}-x^3+3x-4}{x-1}\)
3) \(\lim\limits_{x\rightarrow-\infty}\dfrac{x^3-x^2+1}{2x^2+3x-1}\)
4) \(\lim\limits_{x\rightarrow+\infty}\dfrac{\sqrt{x}+\sqrt[3]{x}+\sqrt[4]{x}}{\sqrt{4x+1}}\)
5) \(\lim\limits_{x\rightarrow-\infty}\dfrac{x+\sqrt{x^2+2}}{\sqrt[3]{8x^3+x^2+1}}\)
6) \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{4x^2+3x-7}}{\sqrt[3]{27x^3+5x^2+x-4}}\)
\(\lim\limits_{x\rightarrow+\infty}\dfrac{x\sqrt{x^2+1}+2x+1}{\sqrt[3]{2x^3+x+1}+x}\)
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{2x^2-x+1}-\sqrt[3]{2x+3}}{3x^2-2}\)
\(\lim\limits_{x\rightarrow+\infty}\dfrac{\sqrt{4x^2+x}+\sqrt[3]{8x^3+x-1}}{\sqrt[4]{x^4+3}}\)
1) limlimits_{xrightarrow0}dfrac{2sqrt{1+x}-sqrt[3]{8-x}}{x}
2)limlimits_{xrightarrow1}dfrac{sqrt[3]{x+7}-sqrt{x+3}}{x^2-3x+2}
3)limlimits_{xrightarrow1}dfrac{sqrt[3]{x^2+7}-sqrt{5-x^2}}{x^2-1}
4)limlimits_{xrightarrow-2}dfrac{sqrt{x+11}-sqrt[3]{8x+43}}{2x^2+3x-2}
5) limlimits_{xrightarrow0}dfrac{sqrt[n]{1+ax}-sqrt[m]{1+bx}}{x}
6)limlimits_{xrightarrow0}dfrac{sqrt{1+4x}.sqrt[3]{1+6x}-1}{x}
Đọc tiếp
1) \(\lim\limits_{x\rightarrow0}\dfrac{2\sqrt{1+x}-\sqrt[3]{8-x}}{x}\)
2)\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[3]{x+7}-\sqrt{x+3}}{x^2-3x+2}\)
3)\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[3]{x^2+7}-\sqrt{5-x^2}}{x^2-1}\)
4)\(\lim\limits_{x\rightarrow-2}\dfrac{\sqrt{x+11}-\sqrt[3]{8x+43}}{2x^2+3x-2}\)
5) \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt[n]{1+ax}-\sqrt[m]{1+bx}}{x}\)
6)\(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{1+4x}.\sqrt[3]{1+6x}-1}{x}\)
Cho \(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-2x+1}{x-1}=3\)
Tính \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{3f\left(x\right)+1}-x-1}{\sqrt{4x+5}-3x-2}\)