\(x\rightarrow-1^-\Rightarrow\left|x+1\right|=1-x\)
\(\Rightarrow\lim\limits_{x\rightarrow-1^-}\dfrac{x\left(x+1\right)\left(x+2\right)}{\left|x+1\right|}=\lim\limits_{x\rightarrow-1^-}\dfrac{x\left(x+1\right)\left(x+2\right)}{1-x}=\dfrac{0}{2}=0\)
Dung ko nhi :D?