(2x - 3)\(^2\) = /3 - 2x/
\(\Rightarrow\) \(\left\{\begin{matrix}2x-3=3-2x\\2x-3=-\left(3-2x\right)\end{matrix}\right.\)
\(\Rightarrow\left\{\begin{matrix}2x+2x=3+3\\2x-2x=-3+3\end{matrix}\right.\)
Mik giải đến đây rùi còn lại bn giải tiếp đi nha! Mik bận rùi
Tìm x: \(\left(2x-1\right)^3-3\left(x+2\right)\left(x-3\right)=\left(3+2x\right)^3-3x\left(x+1\right)\)
Tìm x: \(\left(x-2\right)^3+3\left(2x-3\right)^2=\left(3+x\right)^3-5\left(1+3x\right)^2-\left(x-1\right)\left(3-x\right)\)
Tìm x : \(\left(x-3\right)^2-\left(2x+1\right)^2-2\left(x-1\right)\left(x+2\right)=3\left(x-3\right)-\left(4x-1\right)\left(x+2\right)\)
Tìm x: \(\left(x-3\right)^3+2\left(2x-1\right)^2-2\left(x-1\right)=\left(2+x\right)^3-3\left(1+3x\right)^2\)
Tìm x: \(\left(x-2\right)^3+2\left(1+2x\right)^2=\left(1+x\right)^3-3\left(x-2\right)^2-\left(x-1\right)\)
Tìm x: \(\frac{\left(x-3\right)^2}{3}-\frac{\left(2x+1\right)\left(1-3x\right)}{2}=\frac{x\left(x+2\right)}{3}-\left(1+x\right)^2\)
Tìm x : \(\left(x-3\right)^2-\left(2x+1\right)^2-2\left(x-1\right)\left(x+2\right)=3\left(x-3\right)-\left(4x-1\right)\left(x+2\right)\)
\(\frac{5}{3}\left(3x-3\right)+\frac{1}{2}=\frac{1}{2}\left(2x-1\right)\) \(\frac{-4}{3}\left(x-\frac{1}{4}\right)=\frac{3}{2}\left(2x-1\right)\) ai giup minh voi nhanh nhanh
Tìm x : \(\frac{\left(2x+1\right)^2}{2}-\left|x+1\right|=\frac{\left(x-2\right)^2}{3}-3\left(x+4\right)\)