goi ten kloai la M va co hoa tri la x
CTHH: M2Ox
\(M_2O_x+xH_2\rightarrow2M+xH_2O\)
pt: 2M+16x 2M (g)
de: 4 2,8 (g)
ta co: 8M=5,6M+44,8x
\(\Rightarrow2,4M=44,8x\)
\(\Rightarrow M=\dfrac{56}{3}x\)
bien luan: * \(x=1\Rightarrow M=\dfrac{56}{3}\left(loai\right)\)
* \(x=2\Rightarrow M=\dfrac{112}{3}\left(loai\right)\)
* \(x=3\Rightarrow M=56\left(nhan\right)\)
A, vay kloai do la Fe
Fe2O3: Sat (III) oxit
bazo tuong ung: Fe(OH)3: Sat (III) hidroxit