1.tìm x
a.\(\frac{-5}{8}+x=\frac{4}{9}\)
b.\(1^3_4.x+1^1_2=-\frac{4}{5}\)
c.\(\frac{1}{4}+\frac{3}{4}x=\frac{3}{4}\)
d.\(x.\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
e.\(\frac{3}{35}-\left(\frac{3}{5}+x\right)=\frac{2}{7}\)
f.\(\frac{3}{7}+\frac{1}{7}:x=\frac{3}{14}\)
g.\(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
Tìm x biết
a) -12(x-5)+7(3-x)=15
b) -(2x-3)-4(x+1)=-7x+3
c) -5(x+\(\frac{1}{5}\))-\(\frac{1}{2}\)(x-\(\frac{2}{3}\))=\(\frac{3}{2}\)x-\(\frac{5}{6}\)
d) x-{[-x+(x+3)]-[(x+3)-(x-2)]=0
Tìm x biết: \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
Giá trị x > 0 thỏa mãn: \(\frac{11}{14}+\left|\frac{2}{7}-x\right|-\frac{5}{2}=\frac{4}{3}\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
Find x such that x+2/327 + x+3/326 + x+4/325 + x+5/324 + x+349/5 = 0
Tạm dịch: Tìm x sao cho \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
Mọi người nhớ ghi cách giải và đáp án ra nhé! Cảm ơn mọi người nhìu!!! :)Bài 1 : Tìm x
\(\left(x-\frac{2}{5}\right).\left(x+\frac{3}{7}\right)=0\)
Tìm x , biết \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
giúp mk vs
a. \(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
b.\(-\frac{21}{13}x+\frac{1}{3}=-\frac{2}{3}\)
c. |x-1,5|=2
d.\(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)