Question

I : phân tích đa thức sau thành nhân tử ư

a) a^2+b^2+2ab+2a+2b+1

b) 3x(x-2y)+6y(2y-x)

c) 16xy+4y^2-9+16x^2

Answer 1

a, a²+b²+2ab+2a+2b+1=(a+b+1)²

b,3x(x-2y)+6y(2y-x)=3x(x-2y)-6y(x-2y)

=3(x-2y)(x-2y)=3(x-2y)²

c, 16xy +4y²-9 +16x²=(16x²+16xy+4y²)-3²

=(4x-2y)²-3²=(4x-2y+3)(4x-2y-3)