Question

Giups mik giải pt này với :

1 + \(\dfrac{1}{6}\)+\(\dfrac{120-x}{x+6}\)= \(\dfrac{120}{x}\)

Answer 1

\(1+\dfrac{1}{6}+\dfrac{120-x}{x}=\dfrac{120}{x}\)

\(1+\dfrac{1}{6}+\dfrac{126-\left(x+6\right)}{x+6}=\dfrac{120}{x}\)

\(1+\dfrac{1}{6}-1+\dfrac{126}{x+6}=\dfrac{120}{x}\)

\(\dfrac{1}{6}+\dfrac{126}{x+6}=\dfrac{120}{x}\)

\(\dfrac{126}{x+6}=\dfrac{120}{x}-\dfrac{1}{6}=\dfrac{120.6}{6x}-\dfrac{x}{6x}\)

\(\dfrac{126}{x+6}=\dfrac{126.6-x}{6x}\)

\(126.6.x=\left(126.6.-x\right)\left(x+6\right)\)ok

Answer 2

đk: x khác -6 ,làm toán là khôn khéo, bn tim msc vế trái =6(x+6)

có: (6(x+6) + (x+6) + 6(120-x)) /6(x+6) = 120/x

bây gio bn rut gon r cho tich trung tỷ = ngoai ty la tim dc x