\(\dfrac{2x-3}{-4}=\dfrac{x-1}{3}\) đề ntn phải ko ạ?
`=>3(2x-3)=-4(x-1)`
`=>6x-9=-4x+4`
`=>6x+4x=4+9`
`=>10x=13`
`=>x=13/10`
\(\dfrac{2x-3}{-4}=\dfrac{x-1}{3}\\ 3\left(2x-3\right)=-4\left(x-1\right)\\ 6x-9=-4x+4\\ 6x+4x=9+4\\ 10x=13\\ x=\dfrac{13}{10}\)
`2x- 3/(-4) =x-1/3`
`=> 2x-x= -1/3 + (-3/4)`
`=> x= -13/12`