\(\dfrac{mx+5}{10}+\dfrac{x+10}{4}=\dfrac{m}{20}\)
\(\dfrac{2mx+10}{20}+\dfrac{4x+40}{20}=\dfrac{m}{20}\)
\(2mx+10+4x+40=m\)
\(2mx-m+4x+50=0\)
\(m\left(2x-1\right)+2\left(2x-1\right)+52=0\)
\(\left(m+2\right)\left(2x-1\right)=-52\)
Dễ thấy với \(m=-2\) ta có đẳng thức sai
Với m \(\ne-2\)
\(\left(m+2\right)\left(2x-1\right)=-52\)
\(\Rightarrow2x-1=\dfrac{-52}{m-2}\Rightarrow2x=\dfrac{m-50}{m-2}\)
\(\Rightarrow x=\dfrac{m-50}{2\left(m-2\right)}\)
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