\(\frac{1}{x+2}=\frac{5}{2-x}+\frac{12+x}{x^2-4}\) (1)
đkxđ: \(x\ne\pm2\)
(1)\(\Leftrightarrow\frac{\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\frac{-5\left(x+2\right)+12+x}{\left(x-2\right)\left(x+2\right)}\)
\(\Rightarrow x-2=-5\left(x+2\right)+12+x\)
\(\Leftrightarrow5x=4\)
\(\Leftrightarrow x=\frac{5}{4}\)(thỏa mãn đkxđ)