Phương trình bậc nhất một ẩn
Các câu hỏi tương tự
1) giải phương trình :
a) left(2+3right)left(dfrac{3x+8}{2-7x}+1right)left(x-5right)left(dfrac{3x+8}{2-7x}+1right)
b) dfrac{7x+10}{x+1}left(x^2-x-2right)-dfrac{7x+10}{x+1}left(2x^2-3x-5right)0
c) dfrac{2x+5}{x+3}+1dfrac{4}{x^2+2x-3}-dfrac{3x-1}{1-x}
d) dfrac{13}{2x^2+x-21}+dfrac{1}{2x+7}+dfrac{6}{9-x^2}0
i) dfrac{x-49}{50}+dfrac{x-50}{49}dfrac{49}{x-50}+dfrac{50}{x-49}
k) dfrac{1+dfrac{x}{x+3}}{1-dfrac{x}{x+3}}3
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1) giải phương trình :
a) \(\left(2+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
b) \(\dfrac{7x+10}{x+1}\left(x^2-x-2\right)-\dfrac{7x+10}{x+1}\left(2x^2-3x-5\right)=0\)
c) \(\dfrac{2x+5}{x+3}+1=\dfrac{4}{x^2+2x-3}-\dfrac{3x-1}{1-x}\)
d) \(\dfrac{13}{2x^2+x-21}+\dfrac{1}{2x+7}+\dfrac{6}{9-x^2}=0\)
i) \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)
k) \(\dfrac{1+\dfrac{x}{x+3}}{1-\dfrac{x}{x+3}}=3\)
KH
5 tháng 3 2021 lúc 21:27
Giải phương trình :a,\(\dfrac{2x 1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)b,\(\dfrac{3\left(2x 1\right)}{4}-5-\dfrac{3x 2}{10}=\dfrac{2\left(3x-1\right)}{5}\)\(c,\dfrac{x 1}{2009} \dfrac{x 3}{2007}=\dfrac{x 5}{2005} \dfrac{x 7}{2003}\)\(d,\dfrac{392-x...
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1. dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4}dfrac{2left(2x+1right)}{7}-5
2. x-dfrac{3left(x+30right)}{15}-24dfrac{1}{2}dfrac{7x}{10}-dfrac{2left(10x+2right)}{5}
3. 14dfrac{1}{2}-dfrac{2left(x+3right)}{5}dfrac{3x}{2}-dfrac{2left(x-7right)}{3}
4. dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}
5. dfrac{3left(2x-1right)}{4}-dfrac{3x+1}{10}+1dfrac{2left(3x+2right)}{5}
6. x-dfrac{3}{17}left(2x-1right)dfrac{7}{34}left(1-2xright)+dfrac{10x-3}{2}
7. dfrac{3le...
Đọc tiếp
1. \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
2. \(x-\dfrac{3\left(x+30\right)}{15}-24\dfrac{1}{2}=\dfrac{7x}{10}-\dfrac{2\left(10x+2\right)}{5}\)
3. \(14\dfrac{1}{2}-\dfrac{2\left(x+3\right)}{5}=\dfrac{3x}{2}-\dfrac{2\left(x-7\right)}{3}\)
4. \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
5. \(\dfrac{3\left(2x-1\right)}{4}-\dfrac{3x+1}{10}+1=\dfrac{2\left(3x+2\right)}{5}\)
6. \(x-\dfrac{3}{17}\left(2x-1\right)=\dfrac{7}{34}\left(1-2x\right)+\dfrac{10x-3}{2}\)
7. \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
8. \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
a) x-dfrac{dfrac{x}{2}-dfrac{3+x}{4}}{2}dfrac{2x-dfrac{10-7x}{3}}{3}-left(x-1right)
b) x^2-6x-2+dfrac{14}{x^2-6x+7}0
c) dfrac{8x^2}{3left(1-4x^2right)}dfrac{2x}{6x-3}-dfrac{1+8x}{4+8x}
d) dfrac{13}{left(2x+7right)left(x-3right)}+dfrac{1}{left(2x+7right)}dfrac{6}{x^2-9}
e) left(1-dfrac{2x-1}{x+1}right)^3+6left(1-dfrac{2x-1}{x+1}right)^2dfrac{12left(2x-1right)}{x+1}-20
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a) \(x-\dfrac{\dfrac{x}{2}-\dfrac{3+x}{4}}{2}=\dfrac{2x-\dfrac{10-7x}{3}}{3}-\left(x-1\right)\)
b) \(x^2-6x-2+\dfrac{14}{x^2-6x+7}=0\)
c) \(\dfrac{8x^2}{3\left(1-4x^2\right)}=\dfrac{2x}{6x-3}-\dfrac{1+8x}{4+8x}\)
d) \(\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}=\dfrac{6}{x^2-9}\)
e) \(\left(1-\dfrac{2x-1}{x+1}\right)^3+6\left(1-\dfrac{2x-1}{x+1}\right)^2=\dfrac{12\left(2x-1\right)}{x+1}-20\)
KH
23 tháng 1 2021 lúc 22:02
Giải phương trìnha,dfrac{x-3}{5}6-dfrac{1-2x}{3}b,dfrac{3x-2}{6}-5dfrac{3-2left(x+7right)}{4}c,3left(x-1right)+35xd,dfrac{x+1}{100}+dfrac{x+2}{99}dfrac{x+3}{98}+dfrac{x+4}{97}e,dfrac{59-x}{41}+dfrac{57-x}{43}+dfrac{55-x}{45}+dfrac{53-x}{47}-4f,dfrac{x-90}{10}+dfrac{x-76}{12}+dfrac{x-58}{14}+dfrac{x-36}{16}+dfrac{x-15}{17}15Em mới học về pt nên chưa quen lắm mọi người giúp e với ạ !Nguyễn Việt Lâm Quản lý
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Giải phương trình
\(a,\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
\(b,\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
\(c,3\left(x-1\right)+3=5x\)
\(d,\dfrac{x+1}{100}+\dfrac{x+2}{99}=\dfrac{x+3}{98}+\dfrac{x+4}{97}\)
\(e,\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}=-4\)
\(f,\dfrac{x-90}{10}+\dfrac{x-76}{12}+\dfrac{x-58}{14}+\dfrac{x-36}{16}+\dfrac{x-15}{17}=15\)
Em mới học về pt nên chưa quen lắm mọi người giúp e với ạ !Nguyễn Việt Lâm Quản lý
Giải phương trình:a) dfrac{x+4}{5} - x + 4 dfrac{x}{3} - dfrac{x-2}{2}b) dfrac{4-5x}{6} dfrac{2left(-x+1right)}{2}c) dfrac{-left(x-3right)}{2} - 2 dfrac{5left(x+2right)}{4}d) dfrac{7-3x}{2} - dfrac{5+x}{5} 1
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Giải phương trình:
a) \(\dfrac{x+4}{5}\) - x + 4 = \(\dfrac{x}{3}\) - \(\dfrac{x-2}{2}\)
b) \(\dfrac{4-5x}{6}\) = \(\dfrac{2\left(-x+1\right)}{2}\)
c) \(\dfrac{-\left(x-3\right)}{2}\) - 2 = \(\dfrac{5\left(x+2\right)}{4}\)
d) \(\dfrac{7-3x}{2}\) - \(\dfrac{5+x}{5}\) = 1
Giải các phương trình sau:
1. \(x-\dfrac{\dfrac{x}{2}-\dfrac{3+x}{4}}{2}=\dfrac{2\text{x}-\dfrac{10-7\text{x}}{3}}{2}-x-1\)
2.\(\dfrac{3}{10}\left(1,2-x\right)-\dfrac{5+7x7}{4}=\dfrac{1}{20}\left(9\text{ }x+0,2\right)-\dfrac{12,5x+4,5}{5}\)
Giải phương trình:
a, \(\left(x+1+\dfrac{1}{x}\right)^2=\left(x-1-\dfrac{1}{x}\right)^2\)
b, \(\left(x-1\right)^2+3x^2=0\)
Các chế ơi, còn 10 câu nữa thui, sắp hết rùi.
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JIAYOU!
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Giải các phương trình sau
16) 3left(x+5right)left(x+6right)left(x+7right)8x
17) left(x+6right)^4+left(x+4right)^482
18) left(x^2+6x+10right)^2+left(x+3right)left(3x^2+20x+36right)0
19) 2left(x^2+x+1right)^2-7left(x-1right)^213left(x^3-1right)
20) left(x+2008right)^4+left(x+2009right)^4dfrac{1}{8}
21) x^4+18x13x^2+5
22) dfrac{1}{5x^2}+dfrac{1}{x^2-9x+36}dfrac{1}{x^2-4x+16}
23) dfrac{left(x+1right)^2...
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Các chế ơi, còn 10 câu nữa thui, sắp hết rùi.
FIGHTING!
JIAYOU!
HWAITING!
GAMBATTEYO!
Giải các phương trình sau
16) \(3\left(x+5\right)\left(x+6\right)\left(x+7\right)=8x\)
17) \(\left(x+6\right)^4+\left(x+4\right)^4=82\)
18) \(\left(x^2+6x+10\right)^2+\left(x+3\right)\left(3x^2+20x+36\right)=0\)
19) \(2\left(x^2+x+1\right)^2-7\left(x-1\right)^2=13\left(x^3-1\right)\)
20) \(\left(x+2008\right)^4+\left(x+2009\right)^4=\dfrac{1}{8}\)
21) \(x^4+18x=13x^2+5\)
22) \(\dfrac{1}{5x^2}+\dfrac{1}{x^2-9x+36}=\dfrac{1}{x^2-4x+16}\)
23) \(\dfrac{\left(x+1\right)^2}{x^2+2x+2}-\dfrac{x^2+2x}{\left(x+1\right)^2}=\dfrac{1}{90}\)
24) \(\left(2x^2+x-2013\right)^2+4\left(x^2-5x-2012\right)^2=4\left(2x^2+x-2013\right)\left(x^2-5x-2012\right)\)
25)\(\dfrac{x-4}{x+1}+\dfrac{x-4}{x+1}+\dfrac{8}{3}=\dfrac{x-8}{x+2}+\dfrac{x+8}{x-2}\)
Thanks các cậu vì đã giúp mk