Question

GIẢI PHƯƠNG TRÌNH

(x²-2x)²+5(x²-2x)+4=0

Answer 1

\(\left(x^2-2x\right)^2+5\left(x^2-2x\right)+4=0\)

\(\left(x^2-2x+1\right)\left(x^2-2x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\x^2-2x+4=0\left(vo.no\right)\end{matrix}\right.\)

\(\Rightarrow x=1\)