Question

Giải phương trình sau: 5x-2/6=x+7/3.

Answer 1

`(5x-2)/6=(x+7)/3`

`<=>3(5x-2)=6(x+7)`

`<=>15x-6=6x+42`

`<=>9x=48`

`<=>x=16/3`

Vậy `S={16/3}`

Answer 2

Ta có

 \(5x-\dfrac{2}{6}=x+\dfrac{7}{3}\\ 4x=\dfrac{8}{3}\\ x=\dfrac{2}{3}\)

Answer 3

\(5x-\dfrac{2}{6}=x+\dfrac{7}{3}\)

\(\Leftrightarrow\dfrac{30x}{6}-\dfrac{2}{6}=\dfrac{6x}{6}+\dfrac{14}{6}\)

\(\Leftrightarrow30x-2=6x+14\)

\(\Leftrightarrow24x=16\)

\(\Leftrightarrow x=\dfrac{2}{3}\)

 

Answer 4

Ta có: \(\dfrac{5x-2}{6}=\dfrac{x+7}{3}\\ \dfrac{5x-2}{2}=x+7\\ 5x-2=2x +14\\ 3x=16\\ x=\dfrac{16}{3}\)

Answer 5

`(5x-2)/6=(x+7)/3`

`<=>(5x-2)/6=(2x+14)/6`

`<=>5x-2=2x+14`

`<=>3x=16`

`<=>x=16/3`

Vậy `S={16/3}`