Question

Giải phương trình

a,x-2/x-3>0

Answer 1

\(\dfrac{x-2}{x-3}>0\left(ĐKXĐ:x\ne3\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-2>0\\x-3>0\end{matrix}\right.\\\left\{{}\begin{matrix}x-2< 0\\x-3< 0\end{matrix}\right.\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x>2\\x>3\end{matrix}\right.\\\left\{{}\begin{matrix}x< 2\\x< 3\end{matrix}\right.\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x>3\\x< 2\end{matrix}\right.\)

Answer 2

\(\dfrac{x-2}{x-3}>0\) (đkxđ: x≠3)

<=> x-2 > x-3

<=> x > x-1

Answer 3

Sorry nhầm

\(\dfrac{x-2}{x-3}>0\) ( đkxđ : x≠3)

<=> x-2 > 0

<=> x > 2