a: \(-6\cdot\left(-\dfrac{2}{3}\right)\cdot0.25=6\cdot\dfrac{2}{3}\cdot\dfrac{1}{4}=4\cdot\dfrac{1}{4}=1\)
b: \(\dfrac{-15}{4}\cdot\dfrac{-7}{15}\cdot\left(-2\dfrac{2}{5}\right)\)
\(=\dfrac{7}{4}\cdot\dfrac{12}{5}\)
\(=\dfrac{84}{20}=\dfrac{21}{5}\)
c: \(\left(-2\dfrac{1}{5}\right)\cdot\left(-\dfrac{9}{11}\right)\cdot\left(-\dfrac{1}{14}\right)\cdot\dfrac{2}{5}\)
\(=-\dfrac{11}{5}\cdot\dfrac{2}{5}\cdot\dfrac{9}{11}\cdot\dfrac{1}{14}\)
\(=-\dfrac{11}{11}\cdot\dfrac{2}{14}\cdot\dfrac{9}{25}\)
\(=-\dfrac{9}{175}\)
\(a,=4\cdot0,25=1\\ b,=\dfrac{7}{4}\cdot\left(-\dfrac{12}{5}\right)=-\dfrac{21}{5}\\ c,=\left(-\dfrac{11}{5}\right)\left(-\dfrac{9}{11}\right)\left(-\dfrac{15}{14}\right)\cdot\dfrac{2}{5}\\ =\dfrac{9}{5}\cdot\left(-\dfrac{15}{14}\right)\cdot\dfrac{2}{5}=-\dfrac{27}{14}\cdot\dfrac{2}{5}=-\dfrac{27}{35}\\ d,=\left(-\dfrac{11}{2}\right)\left(-\dfrac{1}{2}\right)+\dfrac{4}{9}=\dfrac{11}{4}+\dfrac{4}{9}=\dfrac{115}{36}\\ e,=\dfrac{5}{4}\cdot\left(-\dfrac{8}{15}\right)-\dfrac{3}{5}-\dfrac{3}{10}=-\dfrac{2}{3}-\dfrac{3}{5}-\dfrac{3}{10}=-\dfrac{47}{30}\)
\(f,B=\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\left(6-1\right)}=\dfrac{2\cdot6}{5\cdot3}=\dfrac{4}{5}\\ g,=\dfrac{5}{8}+\dfrac{9}{4}\cdot\dfrac{5}{3}-\dfrac{5}{24}=\dfrac{5}{8}+\dfrac{15}{4}-\dfrac{5}{24}=\dfrac{25}{6}\\ h,=\dfrac{49}{38}\cdot\left(\dfrac{152}{11}-\dfrac{57}{11}\right):\dfrac{245}{418}=\dfrac{49}{38}\cdot\dfrac{418}{245}\cdot\dfrac{95}{11}=\dfrac{95\cdot11}{5\cdot11}=19\\ k,=\dfrac{11}{30}+\dfrac{18}{35}\cdot\dfrac{35}{54}-\dfrac{18}{35}\cdot\dfrac{49}{18}-\dfrac{18}{35}\cdot\dfrac{28}{48}\\ =\dfrac{11}{30}+\dfrac{1}{3}-\dfrac{7}{5}-\dfrac{3}{10}=-1\)
giúp mik giải 2 bài này vs ạ