Question

Giải các phương trình sau:

a) \(\frac{5x-2}{6}\) + \(\frac{3-4x}{2}\) = 2 - \(\frac{x+7}{3}\) b) \(\frac{x+3}{2x-6}\) - \(\frac{18}{x^2-9}\) = \(\frac{x-3}{6+2x}\) c) \(\frac{x-2}{x+2}\) - \(\frac{3}{x-2}\) = \(\frac{2\left(x-11\right)}{x^2-4}\) Mng bt câu nào thỳ help hộ mk câu đó. R mk tick cho. Tks!!

Answer 1

a, \(\frac{5x-2}{6}+\frac{3-4x}{2}=2\)\(-\frac{x+7}{3}\)

<=> \(\frac{5x-2}{6}+\frac{9-12x}{6}=\frac{12}{6}-\frac{2x+14}{6}\)

=> 5x-2+9-12x = 12-2x-14

<=> 5x-12x+2x = 12-14-9+2

<=> -5x = -9

<=> x = \(\frac{9}{5}\)