a) 1-2x=2-3x
<=> -2x+3x=2-1
<=> x = 1
S={1}
b) \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\)
<=> 3( 3x+2)-(3x+1)=10+12x
<=> 6x+5 = 10+12x
<=>6x-12x=10-5
<=> -6x=5
<=> x= \(\frac{-5}{6}\)
S =\(\left\{\frac{-5}{6}\right\}\)
c) \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\)
<=> 3(2x-1)-5(x-2)= x+7
<=> 6x -3 -5x +10= x+7
<=> x+7 = x+7
S= R