Question

giá trị x+y² biết (\(\left|2x-14\right|\))²⁰¹⁶+(3y+6)²=0

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}\left(\left|2x-14\right|\right)^{2016}=0\\\left(3y+6\right)^2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=7\\y=-2\end{matrix}\right.\)

=>x+y²=7+(-2)²=11

Answer 2