\(\frac{\sqrt{6}-\sqrt{3}}{\sqrt{2}-1}-\frac{2}{\sqrt{3}-1}\\ =\frac{\sqrt{3}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}-\frac{2\left(\sqrt{3}+1\right)}{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)}\\ =\sqrt{3}-\frac{2\left(\sqrt{3}+1\right)}{3-1}\\ =\sqrt{3}-\left(\sqrt{3}+1\right)\\ =\sqrt{3}-\sqrt{3}-1\\ -1\)