*Bài làm:
\(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\)
= \(\frac{3.2^2.2^{16}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
= \(\frac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}\)
= \(\frac{3.2^{18}}{11.2^{35}-2^{36}}\)
= \(\frac{3.2^{18}}{2^{18}.\left(11.2^{17}-2^{18}\right)}\)
= \(\frac{3}{\left(11.2^{17}-2^{18}\right)}\)
= \(\frac{3}{2^{17}.\left(11-2\right)}\)
= \(\frac{3}{2^{17}.9}\)
= \(\frac{1}{2^{17}.3}\)
*Vậy \(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\) = \(\frac{1}{2^{17}.3}\) .