Question

\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)

Answer 1

13/23+x=29/30-7/69

13/23+x=199/230

x=199/230-13/23

x=3/10

Answer 2

\(\dfrac{29}{30}-\left(\dfrac{13}{23}+x\right)=\dfrac{7}{69}\)

\(\dfrac{13}{23}+x=\dfrac{29}{30}-\dfrac{7}{69}\)

\(\dfrac{13}{23}+x=\dfrac{2001}{2070}-\dfrac{210}{2070}\)

\(\dfrac{13}{23}+x=\dfrac{1791}{2070}\)

\(x=\dfrac{1791}{2070}-\dfrac{13}{23}\)

\(x=\dfrac{1791}{2070}-\dfrac{1170}{2070}\)

\(x=\dfrac{621}{2070}=\dfrac{3}{10}\)

Answer 3

\(\dfrac{29}{30}-\left(\dfrac{13}{23}+x\right)=\dfrac{7}{69}\)

\(\dfrac{13}{23}+x=\dfrac{29}{30}-\dfrac{7}{69}\)

\(\dfrac{13}{23}+x=\dfrac{199}{230}\)

\(x=\dfrac{13}{23}-\dfrac{199}{230}\)

\(x=\dfrac{-3}{10}\)

Answer 4

\(\dfrac{29}{30}\)-\(\left(\dfrac{13}{23}+x\right)\)=\(\dfrac{7}{69}\)

\(\dfrac{29}{30}\)-\(\dfrac{13}{23}\)-x =\(\dfrac{7}{69}\)

\(\dfrac{277}{690}\)-x =\(\dfrac{7}{69}\)

x =\(\dfrac{277}{690}\)-\(\dfrac{7}{69}\)

x =\(\dfrac{3}{10}\)