Question

\(\dfrac{x}{2}\)=\(\dfrac{y}{5}\); \(\dfrac{y}{4}\)=\(\dfrac{z}{6}\) và x+y-z=26

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Answer 1

Từ \(\dfrac{x}{2}=\dfrac{y}{5}\Rightarrow\dfrac{x}{8}=\dfrac{y}{20}\)(1)

\(\dfrac{y}{4}=\dfrac{z}{6}\Rightarrow\dfrac{y}{20}=\dfrac{z}{30}\)(2)

Từ (1),(2) \(\Rightarrow\dfrac{x}{8}=\dfrac{y}{20}=\dfrac{z}{30}=\dfrac{x+y-z}{8+20-30}=\dfrac{26}{-2}=-13\)

(ADTCDTSBN và x+y-z=26)

\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{8}=-13\\\dfrac{y}{20}=-13\\\dfrac{z}{30}=-13\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-104\\y=-260\\z=-390\end{matrix}\right.\)

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