Question

\(\dfrac{3+2\sqrt{3}}{\sqrt{3}}\) - \(\dfrac{2}{\sqrt{3}-1}\)

Answer 1

\(=\dfrac{\sqrt{3}\left(\sqrt{3}+2\right)}{\sqrt{3}}-\dfrac{2\left(\sqrt{3}+1\right)}{2}=\sqrt{3}+2-\sqrt{3}-1=1\)

Answer 2

= \(\dfrac{\sqrt{3}\left(\sqrt{3}+2\right)}{\sqrt{3}}-\dfrac{2\left(\sqrt{3}+1\right)}{3-1}\)

= \(\sqrt{3}+2-\sqrt{3}-1\)

= 1