Question

\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)

Answer 1

Giải:

Theo đề ra, ta có:

\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)

\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}=\dfrac{2x+1+3y-2}{5+7}=\dfrac{2x+3y-1}{12}\)

\(\Leftrightarrow\dfrac{2x+3y-1}{6x}=\dfrac{2x+3y-1}{12}\)

Vì \(2x+3y-1=2x+3y-1\) (Tử bằng tử)

\(\Leftrightarrow6x=12\) (Mẫu bằng mẫu)

\(\Leftrightarrow x=\dfrac{12}{6}=2\)

Vậy \(x=2\)

Chúc bạn học tốt!