\(\dfrac{10}{12}+\dfrac{14}{16}=\dfrac{5}{6}+\dfrac{7}{8}=\dfrac{20}{24}+\dfrac{21}{24}=\dfrac{41}{24}\)
\(\dfrac{10}{12}+\dfrac{14}{16}=\dfrac{80}{96}+\dfrac{84}{96}=\dfrac{164}{96}=\dfrac{41}{24}\)
\(\dfrac{10}{12}+\dfrac{14}{16}=\dfrac{5}{6}+\dfrac{7}{8}=\dfrac{40}{48}+\dfrac{42}{48}=\dfrac{82}{48}=\dfrac{41}{24}\)
\(=\dfrac{10.4}{12.4}+\dfrac{14.3}{16.3}\)
\(=\dfrac{40}{48}+\dfrac{42}{48}\)
\(=\dfrac{40+42}{48}\)
\(=\dfrac{82}{48}\)
\(=\dfrac{41}{24}\)
Giải:
\(\dfrac{10}{12}+\dfrac{14}{16}=\dfrac{5}{6}+\dfrac{7}{8}=\dfrac{20}{24}+\dfrac{21}{24}=\dfrac{41}{24}\)
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