Question

đạo hàm

a) \(y=\sqrt{\dfrac{2x-1}{x+1}}\)

b) \(y=4x+\dfrac{3}{2}x^2\)

c) \(y=\dfrac{x^3}{3}-4x^2+7x+1\)

Answer 1

a/ \(y'=\dfrac{1}{2}.\sqrt{\dfrac{x+1}{2x-1}}.\left(\dfrac{2x-1}{x+1}\right)'=\dfrac{1}{2}\sqrt{\dfrac{x+1}{2x-1}}.\dfrac{3}{\left(x+1\right)^2}\)

b/ \(y'=4+3x\)

c/ \(y'=x^2-8x+7\)