a)Ta có:\(\dfrac{1717}{2929}=\dfrac{1717:101}{2929:101}=\dfrac{17}{29}\left(1\right)\)
.\(\dfrac{17171717}{29292929}=\dfrac{17171717:1010101}{29292929:1010101}=\dfrac{17}{29}\left(2\right)\)
Từ (1) và (2)=>\(\dfrac{1717}{2929}=\dfrac{17171717}{29292929}\)
b)Ta có \(\dfrac{3120-34}{4170-41}=\dfrac{3176}{4129}\left(1\right)\)
\(\dfrac{6420-68}{8340-82}=\dfrac{6352}{8258}=\dfrac{6352:2}{8258:2}=\dfrac{3176}{4129}\left(2\right)\)
Từ (1) và (2)=>đpcm