Question

cho goc xoy=120 . vẽ tia Ot, Oz nằm trong góc xOy sao cho Ot ⊥Ox, tia Oz ⊥ Oy. Tính tOz

nhanh giùm mình nha

Answer 1

Ta có: \(\widehat{O_1}+\widehat{yOz}=\widehat{xOy}\) (2 góc kề nhau)

hay \(\widehat{O_1}+90^o=120^o\)

=> \(\widehat{O_1}=120^o-90^o=30^o\)

Lại có: \(\widehat{O_3}+\widehat{xOt}=\widehat{xOy}\) (2 góc kề nhau)

hay \(\widehat{O_3}+90^o=120^o\)

\(\Rightarrow\widehat{O_3}=120^o-90^o=30^o\)

Có: \(\widehat{O_1}+\widehat{O_2}+\widehat{O_3}=\widehat{xOy}\) (các góc kề nhau)

hay \(30^o+\widehat{O_2}+30^o=120^o\)

\(\Rightarrow\widehat{O_2}=120^o-30^o-30^o=60^o\)

hay \(\widehat{tOz}=60^o\)